Matematika Jika x = 2 dan y = 4 serta 1 + z3 = x3 + y2 + (yx) . Berapakah XYZ:

chelseysporerulv – June 09, 2023

Jika x = 2 dan y = 4 serta 1 + z3 = x3 + y2 + (yx) . Berapakah XYZ:

Jawaban:

56

Penjelasan dengan langkah-langkah:

1 + z3 = x3 +y2 + (yx)

xyz?

x3 = 6 + y2 = 8 + (yx) = 8

: 22

1 + z3 ( 22 - 1 = 21 : 3 = 7)

maka, z = 7

XYZ : 2×4×7 = 56

[answer.2.content]